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mini-openclaw-v2/backend/services/review_plan.py
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"""T06-a 方案维度解析:去重、刻度冲突与呈现判定。
依据:docs/v2/14-experience-loop.md §5、03-detailed-design.md §9.2;
BR-28 / E-20 / AC-29 / AC-44。
三条不可妥协的规则:
1. **同 ID 必须语义一致**:标签、量纲(scale_id/version)、刻度层级任一不同即
**拒绝合并**并报冲突,绝不让模型临时猜一个(BR-28)。相同定义只保留一份。
2. **异刻度不强行归一化**:不同刻度的维度不得共用雷达,改为分面展示(14 §5)。
3. **不默默丢失关键项**:呈现判定返回的 radar / listed / hard_block 三组并集
必须等于全部维度;任何维度都要出现在某一组里(AC-44)。
"""
from __future__ import annotations
from contracts.prescreen import DimensionSpec
from services import assistant_store as store
from services import component_registry as registry
RADAR_MIN, RADAR_MAX = 3, 8
EMPTY_REASON = "当前方案尚未配置核查维度"
FACETED_REASON = "维度刻度不一致,分面展示;不强行归一化,避免误导读者比较不可比的量"
RADAR_REASON = "同一刻度且 3–8 维,可用雷达并附等价文字列表"
FEW_REASON = "少于 3 维,用状态条/列表比雷达更清楚"
MANY_REASON = "多于 8 维,雷达会不可读,改为分组/列表且全部维度仍可查看"
def _definition(spec: dict) -> tuple:
"""判据:标签 + 刻度标识/版本 + 层级内容。任一不同即视为不同定义。"""
return (
str(spec.get("label", "")),
str(spec.get("scale_id", "")),
str(spec.get("scale_version", "")),
tuple((level.get("value"), level.get("label"), level.get("criterion"))
for level in spec.get("levels", [])),
)
def _validate(spec: dict) -> dict:
try:
return DimensionSpec(**spec).model_dump(mode="json")
except Exception as exc:
raise ValueError(f"维度不合法:{exc}") from exc
def resolve_dimensions(specs) -> list[dict]:
"""按 dimension_id 合并;同 ID 不同定义 → 冲突拒绝(AC-29 / E-20)。
返回按 order 稳定排序后的维度列表,**同一定义只出现一次**。
"""
merged: dict[str, dict] = {}
for raw in specs or ():
spec = _validate(raw)
existing = merged.get(spec["id"])
if existing is None:
merged[spec["id"]] = spec
continue
if _definition(existing) != _definition(spec):
raise ValueError(
f"维度 {spec['id']} 存在不一致定义(标签/刻度/层级不同),请统一后保存方案;"
"不得由程序或模型临时选择其一"
)
# 完全相同的定义:合并引用,避免重复计数(14 §5)
references = {ref["id"]: ref for ref in existing["component_refs"]}
for ref in spec["component_refs"]:
references.setdefault(ref["id"], ref)
existing["component_refs"] = list(references.values())
existing["required"] = existing["required"] or spec["required"]
return sorted(merged.values(), key=lambda item: (item["order"], item["id"]))
def is_single_scale(dimensions) -> bool:
"""全部维度是否共用同一可解释刻度(可比性前提)。"""
return len({(d["scale_id"], d["scale_version"]) for d in dimensions}) <= 1
def presentation(dimensions, hard_block_ids=()) -> dict:
"""AC-44 的呈现判定:雷达 / 列表 / 分组 / 分面 / 空。
硬阻断维度**单列**,不参与雷达面积(14 §5:不被平均数或面积覆盖)。
"""
ids = [item["id"] for item in dimensions]
if not dimensions:
return {"layout": "empty", "reason": EMPTY_REASON,
"radar_ids": [], "listed_ids": [], "hard_block_ids": []}
blocks = [item_id for item_id in ids if item_id in set(hard_block_ids)]
remaining = [item_id for item_id in ids if item_id not in set(blocks)]
if not is_single_scale(dimensions):
return {"layout": "faceted", "reason": FACETED_REASON,
"radar_ids": [], "listed_ids": remaining, "hard_block_ids": blocks}
count = len(remaining)
if count < RADAR_MIN:
layout, reason, radar = "list", FEW_REASON, []
elif count > RADAR_MAX:
layout, reason, radar = "grouped", MANY_REASON, []
else:
layout, reason, radar = "radar", RADAR_REASON, remaining
listed = [item_id for item_id in remaining if item_id not in set(radar)]
return {"layout": layout, "reason": reason,
"radar_ids": radar, "listed_ids": listed, "hard_block_ids": blocks}
def assert_nothing_dropped(result: dict, dimensions) -> None:
"""呈现判定不得丢失任何维度(AC-44:不默默丢失关键项)。"""
shown = set(result["radar_ids"]) | set(result["listed_ids"]) | set(result["hard_block_ids"])
expected = {item["id"] for item in dimensions}
missing = expected - shown
if missing:
raise ValueError(f"呈现判定丢失了维度:{sorted(missing)}")
if shown - expected:
raise ValueError(f"呈现判定出现了未知维度:{sorted(shown - expected)}")
# ---------------------------------------------------------------- 方案装配(T06-b)
# 依赖不可用时的统一文案(对应 E-19 PLAN_DEPENDENCY_INVALID)。
DEPENDENCY_INVALID = "评审方案存在不可用组件,请更新后重新发起;不暴露无权组件"
REF_GROUPS = ("skills", "rules", "template", "cards")
def _unusable(db, component_id: str) -> str | None:
"""返回不可用原因;可用则 None。
只用**已发布指针**(release)判定:草稿、已撤回、从未发布的组件都没有 release 行,
因此天然被排除——这正是"草稿或已撤回组件不得进入新运行"(BR-27)的机械表达。
"""
try:
pointer = store.get(db, "release", component_id)
except KeyError:
return "尚未发布或已撤回"
try:
version = store.get(db, "component_version", pointer["version_id"])
except KeyError:
return "发布指针指向的版本不存在"
if version.get("status") != "published":
return f'版本状态为 {version.get("status")}'
return None
def check_dependencies(db, plan: dict) -> None:
"""装配前预检:逐个说明**哪个**依赖不可用,而不是抛裸 KeyError。
裸 KeyError 会被 translate() 映射成 404,用户看到"对象不存在",无法定位是哪一项。
"""
problems = []
for group in REF_GROUPS:
keys = plan.get(group) if group != "template" else [plan.get("template")]
for key in [item for item in (keys or []) if item]:
reason = _unusable(db, key)
if reason:
problems.append(f"{group}:{key}({reason})")
if problems:
raise ValueError(f"{DEPENDENCY_INVALID};不可用依赖:{'、'.join(sorted(problems))}")
def assemble(db, plan_id: str, legacy_catalog=None) -> dict:
"""装配并冻结一个评审方案。
不重复实现冻结:解析、原生方法文本冻结、循环依赖与输出冲突检查、数据域一致性、
content_hash 全部委托 `component_registry.freeze()`。本函数只加两件事:
1. 依赖预检,给出可定位的 E-19 文案(而非 404 的"对象不存在")
2. 维度解析与呈现判定(T06-a),并保证维度不丢失
"""
reason = _unusable(db, plan_id)
if reason:
raise ValueError(f"评审方案不可用({reason});{DEPENDENCY_INVALID}")
published_plan = registry.resolve(db, plan_id)
if published_plan.get("kind") != "plan":
raise ValueError("所选组件不是业务评审方案")
check_dependencies(db, published_plan)
frozen = registry.freeze(db, plan_id, legacy_catalog)
dimensions = resolve_dimensions(published_plan.get("dimensions", []))
result = presentation(dimensions)
assert_nothing_dropped(result, dimensions)
frozen["dimensions"] = dimensions
frozen["presentation"] = result
return frozen
# ---------------------------------------------------------------- 方案治理(T06-c)
# ADR-11:Tools 由后台批准,**不开放业务 Tools 卡**。方案只能引用已登记工具,
# 不得自带工具配置面——否则业务侧就能绕过工具白名单。
FORBIDDEN_PLAN_KEYS = ("tools", "tool_cards", "tool_config", "allowed_tools", "permissions")
def _plan_codes(frozen: dict) -> set[str]:
"""方案内产生的核查编码:Skill 的 code 与规则条件的 code。"""
codes = {skill.get("code") for skill in frozen.get("skills", []) if skill.get("code")}
for rule in frozen.get("rules", []):
codes |= {item.get("code") for item in rule.get("conditions", []) if item.get("code")}
return codes
def validate_critical_checks(frozen: dict, critical_check_ids) -> None:
"""关键核查项必须真由本方案的 Skill/规则产生,不能凭空声明。
否则"关键项"就成了无法追溯的标签,会绕过 BR-06 的硬性阻断语义。
"""
declared = list(critical_check_ids or ())
if not declared:
return
available = _plan_codes(frozen)
unknown = sorted(set(declared) - available)
if unknown:
raise ValueError(f"关键核查项不属于本方案的 Skill 或规则:{unknown}")
def propose_plan(db, body: dict, actor: str, project_id: str):
"""提议一份方案草稿。复用既有组件治理,不新建发布路径。"""
forbidden = sorted(key for key in FORBIDDEN_PLAN_KEYS if key in body)
if forbidden:
raise ValueError(
"方案不得自带工具配置面(不开放业务 Tools 卡);"
f"工具由后台治理,请移除:{forbidden}"
)
if body.get("kind") != "plan":
raise ValueError("提案类型必须是 plan")
spec_inputs = body.get("dimensions", [])
resolved = resolve_dimensions(spec_inputs) # 去重与刻度冲突在此拦截
result = presentation(resolved)
assert_nothing_dropped(result, resolved)
return registry.draft(db, dict(body, project_id=project_id, dimensions=resolved), actor)